3g of acetic acid is added to 250mL of 0.1MHCl and the solution made up to 500mL . To 20mL of this solution (1)/(2)mL of 5MNaOH is added. The pH of the solution is ________ [Given: pKa of acetic acid = 4.75, molar mass

JEE Main 20207 JanuaryEvening Shift

Exam: JEE Main
Year: 2020
Date: 7 January
Shift: Evening Shift
Subject: Chemistry
Chapter: Ionic Equilibrium

JEE Main 2020 · 7 January · Evening Shift · Chemistry · Ionic Equilibrium

3g of acetic acid is added to 250mL of 0.1MHCl and the solution...

3g

of acetic acid is added to

250mL

0.1MHCl

and the solution made up to

500mL

. To

20mL

of this solution

\dfrac{1}{2}mL

5MNaOH

is added. The

pH

of the solution is ________
[Given:

pKa

of acetic acid

= 4.75,

molar mass of acetic acid

60g / mol, \log 3 = 0.4771

, Neglect any changes in volume] 3g of acetic acid is added to 250mL of 0.1MHCl and the solution made up to 500mL . To 20mL of this solution (1)/(2)mL

Correct answer

Step-by-step solution

millimole of acetic acid in $20mL = 2$
millimole of $HCl$ in $20mL = 1$
millimole of $NaOH = 2.5$
3g of acetic acid is added to 250mL of 0.1MHCl and the solution made up to 500mL . To 20mL of this solution (1)/(2)mL

$pH = P{K}_{a} + log \dfrac{3 / 2}{2}$
$= 4.74 + \log 3$
$= 4.74 + 0.48 = 5.22$

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