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JEE Main201910 Jan 2019Morning ShiftChemistryIonic EquilibriumActual

A mixture of 100 m mol of Ca ( OH ) 2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL . What is the mass of calcium sulphate formed and the concentration of OH - in resulting solution, respectively? (Molar mass of Ca OH 2 , Na 2 SO 4 and CaSO 4 are 74 , 143 and 136 g   mol - 1 , respectively; K sp of Ca OH 2 is   5 .5 × 10 - 6 )

Options

  1. A1 .9   g ,   0 .14   mol   L - 1
  2. B13 .6   g ,   0 .28   mol   L - 1
  3. C1 .9   g ,   0 .28   mol   L - 1
  4. D13 .6   g ,   0 .14   mol   L - 1

Correct answer

C. 1 .9   g ,   0 .28   mol   L - 1

Step-by-step solution

Mass of CaSO 4 = 14 × 136 1000 = 1 .9   g CaSO 4 = 14 × 136 1000 = 1 .9   g OH - = 28 100 = 0 .28   M

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