JEE Main201815 Apr 2018Evening ShiftChemistryIonic EquilibriumActual
Following four solutions are prepared by mixing different volumes of NaOH and HCl of different concentrations, pH of which one of them will be equal to 1 ?
Options
- A55 ~mL M 10 HCl +45 ~mL M 10 NaOH
- B75 ~mL M 5 HCl +25 ~mL M 5 NaOH
- C100 ~mL M 10 HCl +100 ~mL M 10 NaOH
- D60 ~mL M 10 HCl +40 ~mL M 10 NaOH
Correct answer
B. 75 ~mL M 5 HCl +25 ~mL M 5 NaOH
Step-by-step solution
75 ~mL M 5 HCl +25 ~mL M 5 NaOH 25 ~mL M 5 NaOH will neutralise 25 ~mL M 5 HCl 75-25=50 ~mL M 5 HCl will remain. Total volume will be 75+25=100 ~mL 50 ~mL M 5 HCl is diluted to 100 ~mL [ H ⁺ ]=[ HCl ]= M 5 50 100 = M 10 pH =- ₁₀ [ H ⁺ ]=- ₁₀ M 10 =1