i) There are 9 friends A , B , C , D , E , F , G , H seated in a circle facing the centre. ii) AC , DG , HE and FB are seated adjacent to each other. A is also seated adjacent to H . iii) B is 2^ nd to the right of H . iv) E is 3^ rd to the right of C . Who is 3^ rd to the left of C?

Step-by-step solution

Fixed Sequence Analysis By combining the adjacency and directional constraints, we can establish this specific chain: - The A-Center: Since (A ) must be next to both (C ) and (H ) (from conditions (A C ) and (A H ) ), the arrangement must be (C-A-H ). - Placing B & E: (B ) is (2^ nd ) to the right of (H . E ) is (3^ rd ) to the right of (C ). This places (E ) directly between (H ) and (B ), forming the chain: (C-A-H-E-B ). - Placing F: Since (F ) and (B ) are adjacent, (F ) must sit next to (B ) : (C-A-H-E-B- F ).