JEE Main2013ChemistryIonic EquilibriumActual
Which one of the following arrangements represents the correct order of solubilities of sparingly soluble salts Hg ₂ Cl ₂, Cr ₂ ( SO ₄ )₃ , BaSO ₄ and CrCl ₃ respectively?
Options
- ABaSO ₄> Hg ₂ Cl ₂> Cr ₂ ( SO ₄ )₃> CrCl ₃
- BBaSO ₄> Hg ₂ Cl ₂> CrCl ₃> Cr ₂ ( SO ₄ )₃
- CBaSO ₄> CrCl ₃> Hg ₂ Cl ₂> Cr ₂ ( SO ₄ )₃
- DHg ₂ Cl ₂> BaSO ₄> CrCl ₃> Cr ₂ ( SO ₄ )₃
Correct answer
B. BaSO ₄> Hg ₂ Cl ₂> CrCl ₃> Cr ₂ ( SO ₄ )₃
Step-by-step solution
aligned & Cr ₂ ( SO ₄ )₃ 2 Cr ⁺⁺⁺+3 SO ₄⁻⁻ & K _ sp =(2 s)^2(3 s)^3=4 ~s ^2 27 s^3=108 s^5 & ~s = ( K _ s p 108 )^ 1 / 5 & Hg ₂ Cl ₂ 2 Hg ²⁺+2 Cl ⁻ & K _ sp =(2 s)^2 (2 s)^2=16 s^4 & ~s = ( K _ s p 16 )^ 1 / 4 & BaSO ₄ Ba ⁺⁺+ SO ₄⁻ & K _ sp =s^2 & ~s = K _ sp & CrCl ₃ Cr ³⁺+3 Cl ⁻ & s aligned aligned & K _ sp =s (3 s)^3=27 s^4 & s= ( K _ s p 27 )^ 1 / 4 aligned Hence the correct order of solubilities of salts is K _ sp > ( K _ sp 16 )^ 1 / 4 > ( K _ sp 27 )^ 1 / 4 > ( K _ sp 108 )^ 1 / 5