Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 20127 MayOnline
Exam
JEE Main
Year
2012
Date
7 May
Mode
Online
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2012 · 7 May · Online · Chemistry · Ionic Equilibrium

The solubility (in mol L^ -1 ) of AgCl (K_ sp =1.0 × 10^ -10 ) in...

The solubility (in mol L−1\mathrm{L}^{-1} )of \mathrm{AgCl} \left(K_{sp\mathrm{sp}}=1.0 \times 10^{-10}\right) in a0.1 MKCl\mathrm{M} \mathrm{KCl} solution will be

Options

  1. A1.0×10−91.0 \times 10^{-9}
  2. B1.0×10−101.0 \times 10^{-10}
  3. C1.0×10−51.0 \times 10^{-5}
  4. D1.0×10−111.0 \times 10^{-11}

Correct answer

A. 1.0×10−91.0 \times 10^{-9}

Step-by-step solution

Let solubility of AgCl=xmole/L\mathrm{AgCl}=x \mathrm{ mole} / \mathrm{L}AgCl⇌Ag++Cl−i.e., Ksp(AgCl)=x×xKCl⟶K++Cl−[Cl−]from KCl=0.1m Total [Cl−]in solution =x+0.1Ksp(AgCl)=[Ag+][Cl−]=x(x+0.1)1.0×10−10=x(x+0.1)1.0×10−10=x2+0.1x1.0×10−10=0.1x( as x2<<1)x=1.0×10−9mol/L\begin{aligned} & \mathrm{AgCl} \rightleftharpoons \mathrm{Ag}^{+}+\mathrm{Cl}^{-} \\ & \text{i.e., } K_{\mathrm{sp}(\mathrm{AgCl})}=x \times x \\ & \mathrm{KCl} \longrightarrow \mathrm{K}^{+}+\mathrm{Cl}^{-} \\ & {\left[\mathrm{Cl}^{-}\right] \text{from } \mathrm{KCl}=0.1 \mathrm{ m}} \\ & \text{ Total }\left[\mathrm{Cl}{ }^{-}\right] \text{in solution }=x+0.1 \\ & K_{s p}(\mathrm{AgCl})=\left[\mathrm{Ag}^{+}\right]\left[\mathrm{Cl}^{-}\right]=x(x+0.1) \\ & 1.0 \times 10^{-10}=x(x+0.1) \\ & 1.0 \times 10^{-10}=x^2+0.1 x \\ & 1.0 \times 10^{-10}=0.1 x \quad\left(\text{ as } x^2< < 1\right) \\ & x=1.0 \times 10^{-9} \mathrm{ mol} / \mathrm{L} \end{aligned}
Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

Given is a concentrated solution of a weak electrolyte A_xB_y of concentration 'c' and… JEE Main 2026M_3 A_2 is a sparingly soluble salt of molar mass y g mol ^ -1 and solubility x g L ^ -1… JEE Main 2026Arrange the following resultant mixtures in increasing order of their pH values A. 10 mL… JEE Main 202620 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization.… JEE Main 2026The pH of a solution obtained by mixing 5 mL of 0.1 M NH_4OH solution with 250 mL of 0.1… JEE Main 2026The first and second ionization constants of a weak dibasic acid H_2 A are 8.1 × 10^ -8… JEE Main 2026At 25°C , 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH… JEE Main 2026The solubility product constants of Ag_2CrO_4 and AgBr are 32x and 4y respectively at 298… JEE Main 2026 Full Ionic Equilibrium list All JEE Main PYQs