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JEE Main2007ChemistryIonic EquilibriumActual

In a sautrated solution of the sparingly soluble strong electrolyte AgIO ₃ (Molecular mass =283 ) the equilibrium which sets in is AgIO _ 3( s ) Ag _ ( aq ) ⁺+ IO _ 3( aq ) ⁻ If the solubility product constant K _ sp of AgIO ₃ at a given temperature is 1.0 10⁻⁸ , what is the mass of AgIO ₃ contained in 100 ~ml of its saturated solution?

Options

  1. A28.3 10⁻² ~g
  2. B2.83 10⁻³ ~g
  3. C1.0 10⁻⁷ ~g
  4. D1.0 10⁻⁴ ~g

Correct answer

B. 2.83 10⁻³ ~g

Step-by-step solution

AgIO ₃( s ) Ag ⁺( aq )+ IO ₃⁻( aq ) Let the solubility of AgIO ₃ be s K _ sp = [ Ag ⁺ ] [ IO ₃⁻ ]1.0 10⁻⁸= s ^2 s =10⁻⁴ ~mol / litre = 10⁻⁴ 283 1000 100=283 10⁻⁵=2.83 10⁻³ ~g / 100 ~ml Hence, (B) is correct.

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