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JEE Main2004ChemistryIonic EquilibriumActual

The molar solubility product is K _ sp . ' s ' is given in terms of K _ sp by the relation

Options

  1. As = ( K _ sp 128 )^ 1 / 4
  2. Bs = ( K _ sp 256 )^ 1 / 5
  3. CS = (256 ~K _ sp )^ 1 / 5
  4. Ds = (128 ~K _ sp )^ 1 / 4

Correct answer

B. s = ( K _ sp 256 )^ 1 / 5

Step-by-step solution

Ksp =108 s^51 4^4 s¹⁺⁴=256 s^5= Ksp

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