Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 2004
Exam
JEE Main
Year
2004
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2004 · Chemistry · Ionic Equilibrium

The molar solubility product is K_ sp . ' s ' is given in terms of...

The molar solubility product is Ksp\mathrm{K}_{\mathrm{sp}}. ' s\mathrm{s} ' is given in terms of Ksp\mathrm{K}_{\mathrm{sp}} by the relation

Options

  1. As=(Ksp128)1/4\mathrm{s}=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{128}\right)^{1 / 4}
  2. Bs=(Ksp256)1/5\mathrm{s}=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{256}\right)^{1 / 5}
  3. CS=(256 Ksp)1/5\mathrm{S}=\left(256 \mathrm{~K}_{\mathrm{sp}}\right)^{1 / 5}
  4. Ds=(128 Ksp)1/4\mathrm{s}=\left(128 \mathrm{~K}_{\mathrm{sp}}\right)^{1 / 4}

Correct answer

B. s=(Ksp256)1/5\mathrm{s}=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{256}\right)^{1 / 5}

Step-by-step solution

Ksp=108s5\mathrm{Ksp}=108 s^5 1×44×s1+4=256s5=Ksp1 \times 4^4 \times s^{1+4}=256 s^5=\mathrm{Ksp}
Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

Given is a concentrated solution of a weak electrolyte A_xB_y of concentration 'c' and… JEE Main 2026M_3 A_2 is a sparingly soluble salt of molar mass y g mol ^ -1 and solubility x g L ^ -1… JEE Main 2026Arrange the following resultant mixtures in increasing order of their pH values A. 10 mL… JEE Main 202620 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization.… JEE Main 2026The pH of a solution obtained by mixing 5 mL of 0.1 M NH_4OH solution with 250 mL of 0.1… JEE Main 2026The first and second ionization constants of a weak dibasic acid H_2 A are 8.1 × 10^ -8… JEE Main 2026At 25°C , 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH… JEE Main 2026The solubility product constants of Ag_2CrO_4 and AgBr are 32x and 4y respectively at 298… JEE Main 2026 Full Ionic Equilibrium list All JEE Main PYQs