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Highly selective Backlog Qs for JEE MainChemistryIonic Equilibrium

A solution is 0 . 1 M in Cl - and 0 . 001 M in CrO 4 2 - . Solid AgNO 3 is gradually added to it Assuming that the addition does not change in volume and K sp ( AgCl ) = 1 . 7 × 10 - 10 M 2 and K sp Ag 2 CrO 4 = 1 . 9 × 10 - 12 M 3 . Select correct statement from the following:

Options

  1. AAgCl precipitates first because its K sp is high.
  2. BAg 2 CrO 4 precipitates first as its K sp is low.
  3. CAg 2 CrO 4 precipitates first because the amount of Ag + needed is low.
  4. DAgCl will precipitate first as the amount of Ag + needed to precipitate is low.

Correct answer

D. AgCl will precipitate first as the amount of Ag + needed to precipitate is low.

Step-by-step solution

i Ag + required to ppt AgCl s Ksp = IP = Ag + Cl - = 1 . 7 × 10 - 10 Ag + = 1 . 7 × 10 - 9 ii Ag + required to ppt Ag 2 CrO 4 s Ksp = IP = [ Ag + ] 2 CrO 4 - 2 = 1 . 9 × 10 - 12 Ag + = 4 . 3 × 10 - 5 Ag + required to ppt AgCl is low so AgCl will ppt 1 st .

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