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If the coordinates at one end of a diameter of the circle x²+y²-8 x-4 y+c=0 are (-3,2) , then the coordinates at the other end are

Options

  1. A(5,3)
  2. B(6,2)
  3. C(1,-8)
  4. D(11,2)

Correct answer

D. (11,2)

Step-by-step solution

The centre of the given circle is C (4,2) Let A (-3,2) If ( , ) are the coordinates of the other end of the diameter, then, as the middle ploint of the diameter is the centre, -3 2 =4 and +2 2 =2 =11, =2 Thus, the coordinates of the other end of diameter are (11,2)

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