If the circles described on the line joining the points 0 ,   1 and α ,   β as diameter cuts the axis of x in points whose abscissae are the roots of the equation x 2 -   5 x + 3 = 0 the α ,   β =

Step-by-step solution

Equation of circle in diameter x -   0 x - α +   y -   1 y - β = 0 on x axis y = 0 x 2 - α x   + β = 0   . . . 1 x 2 -   5 x + 3 = 0   . . . 2 Compare equation 1   &   2 α = 5 ,   β = 3