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Highly selective Backlog Qs for JEE MainMathematicsCircle

The equation of the circle which touches the X-axis and Y-axis at the points (1, 0) and (0, 1) respectively is

Options

  1. Ax^2+y^2-4 y+3=0
  2. Bx^2+y^2-2 y+2=0
  3. Cx^2+y^2-2 x-2 y+2=0
  4. Dx^2+y^2-2 x-2 y+1=0

Correct answer

D. x^2+y^2-2 x-2 y+1=0

Step-by-step solution

On plotting the diagram based on the given information, we find centre = (1,1) and radius = 1 Equation of circle, (x-1)^2+(y-1)^2=1^2 x^2+y^2-2 x-2 y+1=0

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