The perpendicular distance from the point (1,2) to common chord of the circles x^2+y^2-2 x+4 y-4=0 and x^2+y^2+4 x-6 y-3=0 is........ units.

Step-by-step solution

Given circle, x^2+y^2-2 x+4 y-4=0 and x^2+y^2+4 x-6 y-3=0 Equation of common chord of circle is S₁-S₂=0 (x^2+y^2-2 x+4 y-4 )- (x^2+y^2+4 x-6 y-3 )=0 array ll & -6 x+10 y-1=0 & 6 x-10 y+1=0 array Perpendicular distance from the point (1,2) to the line 6 x-10 y+1=0 is | 6-20+1 6^2+10^2 |= 13 136