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If for an Arithmetic progression, 9 times nineth term is equal to 13 times thirteenth term, then value of twenty second term is

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Correct answer

A. 0

Step-by-step solution

Let the first term and common difference of given AP be a and d, respectively. Given array l 9 . a₉=13 . a₁₃ 9[a+(9-1) d]=13[a+(13-1) d] 9[a+8 d]=13[a+12 d] 9 a+72 d=13 a+156 d 4 a+84 d=0 4[a+21 d]=0 4[a+(22-1) d=0 a+(22-1) d=0 a₂₂=0 array

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