Highly selective Backlog Qs for JEE MainMathematicsSequences and Series
The sum of n terms of two arithmetic series are in the ratio 2n + 3 : 6n + 5, then the ratio of their 13th terms is
Options
- A53 : 155
- B27 : 87
- C29 : 83
- D31 : 89
Correct answer
A. 53 : 155
Step-by-step solution
Since, S n 1 S n 2 = 2n + 3 6n + 5 ...(i) ⇒ n 2 2a 1 + n - 1 d 1 n 2 2a 2 + n - 1 d 2 = 2n + 3 6n + 5 ⇒ a 1 + n - 1 2 d 1 a 2 + n - 1 2 d 2 = 2n + 3 6n + 5 Put n - 1 2 = 12 ⇒ n = 25 ∴ a 1 + 1 2 d 1 a 2 + 1 2 d 2 = 5 3 1 5 5 ⇒ T 1 3 1 T 1 3 2 = 5 3 1 5 5