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Highly selective Backlog Qs for JEE MainPhysicsCenter of Mass, Momentum and Collision

At a given instant of time two particles are having the position vectors 4 i +4 j +57 k metres and 2 i +2 j +5 k respectively. If the velocity of the first particle be 0.4 i ms ⁻¹ , the velocity of second particle in metre per second if they collide after 10 sec is

Options

  1. A6 ( i - j + 1 3 k )
  2. B0.6 ( i - j + 1 3 k )
  3. C6 ( i + j + 1 3 k )
  4. D0.6 ( i + j - 1 3 k )

Correct answer

B. 0.6 ( i - j + 1 3 k )

Step-by-step solution

aligned s₁+ (u₁ ) t & =s₂+ (u₂ ) t & =(4 i -4 j +7 k )+(0.4 i ) 10 & =(2 i +2 j +5 k )+ (u₂ ) 10 u₂ & = (6 i -6 j +2 k ) 10 & =0.6 [ i - j + 1 3 k ] aligned

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