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Highly selective Backlog Qs for JEE MainPhysicsCenter of Mass, Momentum and Collision

Two particles of equal mass have velocities v ₁=4 i and v ₂=4 j ms ⁻¹ . First particle has an acceleration a ₁=(5 i +5 j ) ms ⁻² while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of

Options

  1. Astraight line
  2. Bparabola
  3. Ccircle
  4. Dellipse

Correct answer

A. straight line

Step-by-step solution

aligned & v _ CM = m₁ v ₁+m₂ v ₂ m₁+m₂ & = v ₁+ v ₂ 2 ( as m₁=m₂ ) & and a _ CM = m₁ a ₁+m₂ a ₂ m₁+m₂ = a ₁+0 2 = a ₁ 2 aligned The centre of mass of two particles will move with the mean velocity of two particles having common acceleration a 2 . Hence, path of CM will be a straight line.

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