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Two particles of equal mass m go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

Options

  1. A1 2 G m R
  2. B4 G m R
  3. CG m 2 R
  4. D1 2 R 1 G m

Correct answer

A. 1 2 G m R

Step-by-step solution

From given condition Gmm (2 R )² = mv ² R , v = Gm 4 R = 1 2 Gm R

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