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A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:

Options

  1. A92 ± 1.8 s
  2. B92 ± 3 s
  3. C92 ± 2 s
  4. D92 ± 5.0 s

Correct answer

C. 92 ± 2 s

Step-by-step solution

T T s T i - T t 1 90 - 2 t 2 91 - 1 t 3 95 3 t 4 92 0 T i 92 Σ |T i - T| N = 1.5 T r = 9 2 ± 1.5 T r = 9 2 ± 2 Because least count of clock is 1s

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