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A small hole of area cross-section 2 m m 2 is present near the bottom of a fully filled open tank of height 2 m . Taking g = 10 m s - 2 , the rate of flow of water through the open hole would be nearly

Options

  1. A12.6 × 1 0 - 6 m 3 s - 1
  2. B8.9 × 1 0 - 6 m 3 s - 1
  3. C2.23 × 1 0 - 6 m 3 s - 1
  4. D6.4 × 1 0 - 6 m 3 s - 1

Correct answer

A. 12.6 × 1 0 - 6 m 3 s - 1

Step-by-step solution

Velocity of efflux v = 2 g h v = 2 × 10 × 2 = 2 × 10 Rate of flow = area × v = 2 × 10 - 6 × 2 × 10 = 4 × 3.14 × 10 - 6 ≅ 12.6 × 10 - 6

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