Highly selective Backlog Qs for JEE MainPhysicsMechanical Properties of Fluids
A solid sphere of volume V and density floats at the interface of two immiscible liquids of densities ₁ and ₂ respectively. If ₁ < < ₂ , then the ratio of volume of the parts of the sphere in upper and lower liquid is
Options
- A- ₁ ₂-
- B₂- - ₁
- C+ ₁ + ₂
- D+ ₂ + ₁
Correct answer
B. ₂- - ₁
Step-by-step solution
V= Volume of solid sphere. Let V₁= Volume of the part of the sphere immersed in a liquid of density ₁ and V₂= Volume of the part of the sphere immersed in liquid of density ₂ . According to law of floatation, Hence from eqns (i) and (ii), aligned & V₁ g+V₂ g=V₁ ₁ g+V₂ ₂ g & or V₁ ( - ₁ ) g=V₂ ( ₂- ) g & or V₁ V₂ = ₂- - ₁ aligned