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An iron rod of length 2 ~m and cross-sectional area of 50 ~mm ² stretched by 0.5 ~mm , when a mass of 250 ~kg is hung from its lower end. Young's modulus of iron rod is

Options

  1. A19.6 10²⁰ ~N / m ²
  2. B19.6 10¹⁸ ~N / m ²
  3. C19.6 10¹⁰ ~N / m ²
  4. D19.6 10¹⁵ ~N / m ²

Correct answer

C. 19.6 10¹⁰ ~N / m ²

Step-by-step solution

Y= F / A / = 250 9.8 50 10⁻⁶ 0.5 10⁻³ 2 = 250 9.8 50 10⁻⁶ 2 0.5 10⁻³ 19.6 10¹⁰ ~N / m ²

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