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A steel rod is projecting out of a rigid wall. The shearing strength of steel is 345   MN   m - 2 . The dimensions AB = 5   cm ,   BC = BE = 2   cm . The maximum load that can be put on the face ABCD is : (neglect bending of the rod) ( g = 10   m   s - 2 )

Options

  1. A3450 kg
  2. B1380 kg
  3. C13800 kg
  4. D345 kg

Correct answer

C. 13800 kg

Step-by-step solution

F = shear strength x area on which shear stress acts = 3 4 5 × 1 0 6 × 4 × 1 0 - 4 = 1 3 8 0 0 0 N So the mass that can be placed = 1 3 8 0 0 kg

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