Highly selective Backlog Qs for JEE MainPhysicsMotion in One Dimension
Given below are the equations of motion of four particles A, B, C and D x A = 6 t - 3 ; x B = 4 t 2 - 2 t + 3 ; x C = 3 t 3 - 2 t 2 + t - 7 ; x D = 7 cos 60 o - 3 sin 30 o The particle moving with constant acceleration is
Options
- AA
- BB
- CC
- DD
Correct answer
B. B
Step-by-step solution
x A = 6 t - 3 v A = d d t 6 t - 3 = 6 Particle A moves with constant velocity. v B = d d t 4 t 2 - 2 t + 3 = 8 t - 2 , a B = d d t 8 t - 2 = 8 Particle B moves with constant acceleration v C = d d t 3 t 3 - 2 t 2 + t - 7 = 9 t 2 - 4 t + 1 a C = 18 t - 4 So, the particle moves with variable acceleration. x D = 7 cos 60 o - 3 sin 30 o Since x D does not depend upon time therefore particle is at rest.