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JEE Main
Exam
JEE Main
Subject
Physics
Chapter
Motion in Two Dimensions

JEE Main · Physics · Motion in Two Dimensions

A missile is fired for maximum range with a initial velocity of 20...

A missile is fired for maximum range with a initial velocity of 20 m/s20 \mathrm{~m} / \mathrm{s}. If g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2, the range of the missile is

Options

  1. A50 m50 \mathrm{~m}
  2. B60 m60 \mathrm{~m}
  3. C20 m20 \mathrm{~m}
  4. D40 m40 \mathrm{~m}

Correct answer

D. 40 m40 \mathrm{~m}

Step-by-step solution

For maximum range of projectile θ\theta will be 45∘45^{{}^{{}^{\circ}}} by the law of projectile motion ∴Rmax⁡=u2g\therefore \quad R_{\max }=\frac{u^2}{g} Given, u=20 ms−1\quad u=20 \mathrm{~ms}^{-1} and g=10 ms−2g=10 \mathrm{~ms}^{-2}Rmax⁡=(20)210=40010Rmax⁡=40 m\begin{aligned} & R_{\max }=\frac{(20)^2}{10}=\frac{400}{10} \\ & R_{\max }=40 \mathrm{~m} \end{aligned}$$
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