Highly selective Backlog Qs for JEE MainPhysicsMotion in Two Dimensions
A fighter plane enters inside the enemy territory, at time t = 0 with velocity v 0 = 250 m s - 1 and moves horizontally with constant acceleration a = 20 m s - 2 (see figure). An enemy tank, at the border, spots the plane and fire shots at an angle θ = 60 ° with the horizontal and with velocity u = 600 m s - 1 .The altitude H , where the plane can be hit by the shot, is
Options
- A1500 3 m
- B125 m
- C1400 m
- D2473 m
Correct answer
D. 2473 m
Step-by-step solution
If being hit, then horizontal distance remains same. v x = 600 cos 60 ο = 300 m s - 1 250 m s - 1 t + 1 2 20 t 2 = 300 t 50 t = 1 2 20 t 2 t = 0 or t = 5 H = 600 sin 60 ο t - 1 2 g t 2 = 600 3 2 × 5 - 1 2 · 10 25 H = 300 3 5 - 125 m H = 2473 m