A stone is projected with a velocity 20 2 m s - 1 at an angle of 45 ° to the horizontal. The average velocity of stone during its motion from starting point to its maximum height is ( g = 10 m s - 2 )

Step-by-step solution

Refer figure are when projectile is at A, then OC = R 2 = 1 2 u 2 g sin 2 θ = 1 2 × 2 0 2 2 1 0 sin 2 × 4 5 ∘ = 40 AC = H = u 2 sin 2 θ 2 g = 2 0 2 2 2 × 1 0 sin 2 4 5 ∘ ∴ Displacement, OA = OC 2 + CA 2 = 4 0 2 + 2 0 2 Time of projectile from O to A = 1 2 2 u sin θ g = u sin θ 2 g = 2 0 2 sin 4 5 ∘ 1 0 = 2 s = 4 0 2 + 2 0 2 2 = 1 0 5 ms - 1 Average velocity = displacement time = 4 0 2 + 2 0 2 2 = 1 0 5 ms - 1