Highly selective Backlog Qs for JEE MainPhysicsMotion in Two Dimensions
A projectile is launched with an initial speed of 40   m   s - 1 at an angle 30 ° above the ground. The projectile lands on a hillside 2 . 0   s later. The net displacement from where the projectile was launched to where it hits the target is (Take g = 10   m   s - 2 )
Options
- A20 3   m
- B30 2   m
- C40   m
- D20 13   m
Correct answer
D. 20 13   m
Step-by-step solution
Horizontal displacement covered, x = 40 cos 30 ° × 2 = 40 3   m Vertical displacement covered, y = 40 sin 30 ° × 2 + 1 2 - 10 × 2 2 = 40 - 20 = 20   m Hence, required displacement will be, x 2 + y 2 = 20 13   m