Most Important Selected Qs for JEE AdvancedChemistryIonic Equilibrium
To 100 ml of an aqueous solution of 0.1 M CH ₃ COOH ( Ka =2 10⁻⁵ ), 0.01 ~mol of HCl ( g ) is passed. Select correct options regarding the resulting solution.
Options
- ADegree of dissociation of acetic acid in resulting solution is 10⁻⁴
- BpH of resulting solution is nearly 1
- CDegree of dissociation of water in resulting solution is 1.8 10⁻¹⁵
- DConcentration of OH ⁻ ions contributed by water is resulting solution is 10⁻⁷ M .
Correct answer
C. Degree of dissociation of water in resulting solution is 1.8 10⁻¹⁵
Step-by-step solution
aligned & ^n CH ₃ COOH =0.1 0.1=0.01 ~mol . & ^ n HCl =0.01 ~mol & [ H ⁺ ]_ f = 0.01 0.1 =0.1 M & pH =1 & CH ₃ COOH CH ₃ COO ⁻+ H ⁺ & 0.1- x x ( x +0.1) & 2 10⁻⁵= x 0.1 0.1 & x =2 10⁻⁵ & array l CH ₃ COOH = 2 10⁻⁵ 0.1 =2 10⁻⁴ H ₂ O H ⁺+ OH ⁻, 10⁻¹⁴=0.1 [ OH ⁻ ] [ OH ⁻ ]=10⁻¹³ M array & ( H ₂ O )= 10⁻¹³ 1000 18 & =18 10⁻¹⁶=1.8 10⁻¹⁵ aligned