Most Important Selected Qs for JEE AdvancedMathematicsContinuity and Differentiability
Let f(x)= ⁻¹( 2 x) and g(x)=| x| then
Options
- Anumber of solution of f(x)=g(x) in [0,2 ] is 4 .
- Bf(x), g(x) is a periodic function
- Cf(x), g(x) is a non differentiable function for some x ,
- Df ( x ), g ( x ) is an even function
Correct answer
D. f ( x ), g ( x ) is an even function
Step-by-step solution
f(x)= ⁻¹( 2 x), g(x)=| x|f(x) , and g(x) both are even and periodic so max f(x), g(x) and f(x), g(x) will also be periodic and even. but f(x), g(x) will be non-differentiable when f(x)=g(x) no of points where f(x)=g(x) are four in [0,2 ]