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JEE Main20266 April 2026Evening ShiftMathematicsContinuity and DifferentiabilityActual

Let f(x) = cases x^3 + 8 ; & x Then the number of points, where the function g f is discontinuous, is __________.

Correct answer

0

Step-by-step solution

The possible points of discontinuity for the composite function g(f(x)) are the points where f(x) is discontinuous and the points where f(x) is equal to a point of discontinuity of g(x) . First, we find the points of discontinuity of f(x) and g(x) . For f(x) , the only possible point of discontinuity is at x = 0 . _ x 0^- f(x) = _ x 0^- (x^3 + 8) = 8 _ x 0^+ f(x) = _ x 0^+ (x^2 - 4) = -4 Since _ x 0^- f(x) _ x 0^+ f(x) , f(x) is discontinuous at x = 0 . For g(x) , the only possible point of discontinuity is at x =

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