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Most Important Selected Qs for JEE AdvancedMathematicsInverse Trigonometric Functions

Let f(x)= ⁻¹ ( 2 x 1+x^2 ), g(x)= ⁻¹ ( 1-x^2 1+x^2 ) and h(x)= ⁻¹ ( 2 x 1-x^2 ) , then:

Options

  1. Af(x)+2 ⁻¹ x= x 1
  2. Bf(x) g(x) =1 x [0,1]
  3. Cg(x)+h(x)= x (-1,0)
  4. D_ x 1⁺ (f(x)+g(x)+h(x)) _ x 1⁻ (f(x)+g(x)+h(x)) =3

Correct answer

C. g(x)+h(x)= x (-1,0)

Step-by-step solution

aligned & f(x)= ⁻¹ ( 2 x 1+x^2 )= cases 2 ^1 x, & -1 x 1 -2 ⁻¹ x, & x 1 - -2 ⁻¹ x, & x -1 cases & g(x)= ⁻¹ ( 1-x^2 1+x^2 )= cases 2 ⁻¹ x, & x 0 -2 ⁻¹ x, & x 1 cases aligned

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