Most Important Selected Qs for JEE AdvancedMathematicsInverse Trigonometric Functions
Let f(x)= ⁻¹ ( 2 x 1+x^2 ), g(x)= ⁻¹ ( 1-x^2 1+x^2 ) and h(x)= ⁻¹ ( 2 x 1-x^2 ) , then:
Options
- Af(x)+2 ⁻¹ x= x 1
- Bf(x) g(x) =1 x [0,1]
- Cg(x)+h(x)= x (-1,0)
- D_ x 1⁺ (f(x)+g(x)+h(x)) _ x 1⁻ (f(x)+g(x)+h(x)) =3
Correct answer
C. g(x)+h(x)= x (-1,0)
Step-by-step solution
aligned & f(x)= ⁻¹ ( 2 x 1+x^2 )= cases 2 ^1 x, & -1 x 1 -2 ⁻¹ x, & x 1 - -2 ⁻¹ x, & x -1 cases & g(x)= ⁻¹ ( 1-x^2 1+x^2 )= cases 2 ⁻¹ x, & x 0 -2 ⁻¹ x, & x 1 cases aligned