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The sum of the first three numbers in an A.P. is 24 and their product is 384. Then which of the following hold(s) good?

Options

  1. Asum of n terms can be 2n(n + 1)
  2. Bsum to n terms can be 2n(n + 3)
  3. Csum of n terms can be 14 n-2 n^2
  4. Dsum of the squares of the three numbers is 224

Correct answer

D. sum of the squares of the three numbers is 224

Step-by-step solution

Let the number be (a-d), a,(a+d)3 a=24a=8 Also (8-d)(8)(8+d)=384 aligned & d^2=16 & d=4 or -4 aligned Hence series is 4,8,12, . aligned & S_n=2 n(n+1) or 12,8,4, & S_n=14 n-2 n^2 aligned

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