Most Important Selected Qs for JEE AdvancedMathematicsTrigonometry

If a x+ x+1= cosec x then the possible values of x can be

Options

Ax=n , a R, n I
Bx=(4 n+1) 2 , a R, n I
Cx= 1 2 ⁻¹ ( 4(a+1) a^2 ), a (- , 2-2 2 ] [2+2 2 , )- -1
Dnone of these

Correct answer

C. x= 1 2 ⁻¹ ( 4(a+1) a^2 ), a (- , 2-2 2 ] [2+2 2 , )- -1

Step-by-step solution

aligned & x+ x=1-a x x & a^2 ^2 x ^2 x-2(a+1) x x=0 & 2 x ( a^2 2 2 x-2(a+1) )=0 aligned Hence 2 x=0 a R x= n 2 , n I And 2 x= 4(a+1) a^2 a (- , 2-2 2 ] [2+2 2 , )

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