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JEE Advanced

Exam: JEE Advanced
Subject: Mathematics
Chapter: Trigonometry

JEE Advanced · Mathematics · Trigonometry

The number of real root(s) of the equation x^2 x=1 lie(s) between 0...

The number of real root(s) of the equation

x^2 \tan x=1

lie(s) between 0 and

2 \pi

is/are

The number of real root(s) of the equation x^2 x=1 lie(s) between 0 and 2 π is/are

The number of real root(s) of the equation x^2 x=1 lie(s) between 0 and 2 π is/are

Options

A $1$
B $2$
C $3$
D $4$

Correct answer

B. $2$

Step-by-step solution

y=\tan x=\frac{1}{x^2}

From graph it is clear that it will have two real roots, The number of real root(s) of the equation x^2 x=1 lie(s) between 0 and 2 π is/are

The number of real root(s) of the equation x^2 x=1 lie(s) between 0 and 2 π is/are

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