Most Important Selected Qs for JEE AdvancedPhysicsCenter of Mass, Momentum and Collision
A small ball of mass m is placed in a circular tube of mass M and radius R in gravity free space. Friction is absent between tube and ball. Ball is given a velocity v ₀ as shown. Then,
Options
- APath of ball from centre of mass of system will be circular.
- BPath of ball from centre of mass of system will be elliptical
- CRadius of curvature of ball at the time of projection of ball is M R m+M
- DNormal force between tube and ball if M=2 m , at the time of projection of ball is 2 m V₀^2 3 R
Correct answer
D. Normal force between tube and ball if M=2 m , at the time of projection of ball is 2 m V₀^2 3 R
Step-by-step solution
From centre of mass of system ball and centre of tube moves in circular path. Radius of curvature of ball at the time of projection of ball is M R m+M Normal force between tube and ball if M=2 m , at the time of projection of ball is aligned & V_ c m = m V₀ m+M & N=m ( (V₀-V_ c m )^2 r₁ ) aligned