Most Important Selected Qs for JEE AdvancedPhysicsElectromagnetic Induction
A frame a bed and a sliding rod PQ of resistance R, start moving with the velocities v and 2 v respectively parallel to a long wire carrying steady current I, as shown in the figure.
Options
- Acharge on the capacitor at time t is q= C ₀ i v 2 2 [1-e^ -U / R C ]
- Bcharge on the capacitor at time t is q= C ₀ iv 2 [1- e ^ - t / Rc ]
- Ccurrent passing through the resistor at time t is i= ₀ ivin 2 2 R [e^ -U R C ]
- Dcurrent passing through the capacitor at time t is i = ₀ iv 2 R [ e ^ -t / R C ]
Correct answer
C. current passing through the resistor at time t is i= ₀ ivin 2 2 R [e^ -U R C ]
Step-by-step solution
aligned & _ P C = v ₀ i 2 2 & _ P Q = 2 v_ ₀ i 2 2 & _ net = ₀ i v 2 2 & q=C [1-e^ -t R C ] & i= R e^ -t / R C aligned