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Quarter non-conducting disc of radius 4 R having uniform surface charge density is placed in xz-plane then which of the following is the correct :

Options

  1. Aelectric potential at (0,3 R, 0) is R 4 ₀
  2. Belectric potential at (0,0,0) is R 2 ₀
  3. Celectric field at (0,3 R, 0) is symmetric with x and z axis
  4. Delectric field intensity at (-4 R, 0,-4 R) is equally inclined with x and z axis

Correct answer

D. electric field intensity at (-4 R, 0,-4 R) is equally inclined with x and z axis

Step-by-step solution

(1) v= ₀^ 4 R ~K 2 rdr r ^2+(3 R)^2 = R 4 ₀ (2) v= ₀^ 4 r K 2 r d r r = R 2 ₀

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