Most Important Selected Qs for JEE AdvancedPhysicsMechanical Properties of Fluids
n drops of a liquid, each with surface energy E , joining to form a single drop
Options
- Asome energy will be released in the process
- Bsome energy will be absorbed in the process
- Cthe energy released or absorbed will be E ( n - n ^ 2 / 3 )
- Dthe energy released or absorbed will be nE (2^ 2 / 3 -1 )
Correct answer
C. the energy released or absorbed will be E ( n - n ^ 2 / 3 )
Step-by-step solution
E = T 4 r ^2 4 3 R ^3= n 4 3 r ^3 n = R ^3 r ^3 R = n ^ 1 / 3 r Surface energy of big drop E^ =T 4 R^2=T 4 n^ 2 / 3 r^2=E^ 2 / 3 Energy released = nE - E ^ = nE - n ^ 2 / 3 E = E ( n - n ^ 2 / 3 )