Most Important Selected Qs for JEE AdvancedPhysicsMotion in Two Dimensions
A particle starts moving with initial velocity 3 ~m / s along x -axis from origin. Its acceleration is varying with x in parabolic nature as shown in figure. At x= 3 ~m tangent to the graph makes an angle 60^ with positive x -axis as shown in diagram. Then at x= 3
Options
- Av = ( 3 +9) m / s
- Ba=1.5 ~m / s ^2
- Cv= 12 ~m / s
- Da=3 ~m / s ^2
Correct answer
B. a=1.5 ~m / s ^2
Step-by-step solution
aligned & a=k x^2 & d a d x =2 k x 60^ =2 k 3 k= 1 2 & a= x^2 2 & v d v d x = x^2 2 v^2 2 = x^3 6 +C₁ at x=0, v=3 ~m / s & C₁= 9 2 & v^2= x^3 3 +9 aligned hence, a =1.5 and v = 3 +9