The position vector of a particle is given by the relation r = (1- + t^2 ) , where is a constant vector while, and are positive constants. Which of the following statement is true?

Step-by-step solution

r ₁= (1- + t^2 ) , as is constant so magnitude of the position vector is increasing but the direction of position vector is constant. Hence motion is a straight line motion Displacement ( x )= F _ t - r ₀= ( t ^2- t ) Velocity; v = d x dt = (2 t - ) Acceleration a =2 As the motion is straight line motion speed is same as the magnitude of velocity