Most Important Selected Qs for JEE AdvancedPhysicsMotion in Two Dimensions
At what angle should a body be projected with a velocity 24 ~ms ⁻¹ just to pass over the obstacle 14 m high at a distance of 24 m . [Take g =10 ~ms ⁻² ]
Options
- A=1
- B=2
- C=3
- D=19 / 5
Correct answer
D. =19 / 5
Step-by-step solution
x=24=u . t t= 24 24 = 1 y=14=u t- 1 2 g t^2 14= u - 5 ^2 aligned & 14=u -5 ^2 & 5 ^2 -24 +19=0 & =1,19 / 5 . Ans aligned