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Most Important Selected Qs for JEE AdvancedPhysicsWaves and Sound

For a certain transverse standing wave on a long string, an antinode is formed at x =0 and next to it, a node is formed at x=0.10 ~m . the position y(t) of the string particle at x=0 is shown in figure.

Options

  1. ATransverse displacement of the particle at x =0.05 ~m and t =0.05 ~s is -2 2 ~cm .
  2. BTransverse displacement of the particle at x =0.04 ~m and t =0.025 ~s is -2 2 ~cm .
  3. CSpeed of the travelling waves that interfere to produce this standing wave is 2 ~m / s .
  4. DThe transverse velocity of the string particle at x = 1 15 ~m and t =0.1 ~s is 20 ~cm / s

Correct answer

D. The transverse velocity of the string particle at x = 1 15 ~m and t =0.1 ~s is 20 ~cm / s

Step-by-step solution

4 =0.1 =0.4 ~m from graph T =0.2 sec . and amplitude of standing wave is 2 A=4 ~cm . Equation of the standing wave aligned & y(x, t)=-2 A ( 2 0.4 x ) ( 2 0.2 t ) cm & y(x=0.05, t=0.05)=-2 2 ~cm & y(x=0.04, t=0.025)=-2 2 36^ & speed = T =2 ~m / sec . & V_y= d y d t =-2 A 2 0.2 ( 2 x 0.4 ) ( 2 t 0.2 ) & V_y= (x= 1 15 m, t=0.1 )=20 ~cm / sec . aligned

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