Most Important Selected Qs for JEE AdvancedPhysicsWaves and Sound
A standing wave of time period T is set up in a string clamped between two rigid supports. At t =0 antinode is at its maximum displacement 2 A .
Options
- AThe energy density of a node is equal to energy density of an antinode for the first time at t = T / 4 .
- BThe energy density of node and antinode becomes equal after T / 2 second.
- CThe displacement of the particle at antinode at t= T 8 is 2 A
- DThe displacement of the particle at node is zero
Correct answer
D. The displacement of the particle at node is zero
Step-by-step solution
Equation of S H M of particle who is at antinode is y =2 ~A ( 2 T ) t at time t = T 8 y =2 ~A 4 = 2 A Displacement of particle at note is always zero.