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Let f: R⁺ (-7, ) be a function defined by f(x)= x^3-7 x^2+1 and g be the inverse of f such that 1 g ( 1 ^2+1 )=1 for some . If k= g( +1) g(g( )) then find the value of k .

Correct answer

1

Step-by-step solution

gathered g ( 1 ^2+1 )= f( )= 1 ^2+1 =2 k= g( +1) g(g( )) = g(3) g(g(2)) = g(3) g(3) =1 gathered

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