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Let L= _ n=3 ^ (1- 4 n^2 ), M= _ n=2 ^ ( n^3-1 n^3+1 ) and N= _ n=1 ^ (1+n⁻¹ )^2 1+2 n⁻¹ , then find the value of (L⁻¹+M⁻¹+N⁻¹ ) .

Correct answer

8

Step-by-step solution

aligned & L= _ n=3 ^ (1- 4 n^2 )= _ n=3 ^ ( n^2-4 n^2 )= _ n=3 ^ ( n-2 n ) _ n=3 ^ ( n+2 n ) & L= ( 1 3 2 4 3 5 4 6 n-2 n ) ( 5 3 6 4 7 5 (n+1) n-1 (n+2) n ) & L= ( 1 2 n(n-1) (n+1)(n+2) 3 4 )= n (1+ 1 n ) n (1+ 2 n ) n^2 (1- 1 n ) 2 3 4 = 1 6 L= 1 6 & M= _ n=2 ^ ( n^3-1 n^3+1 )=M= _ n=2 ^ n-1 n+1 (n^2+n+1 ) (n^2-n+1 ) & = ( 1 3 2 4 3 5 4 6 n-2 n n-1 n+1 ) ( 7 3 13 7 21 3 n^2+n+1 n^2-n+1 ) & = _ n 2 n(n+1) n^2+n+1 3 = 2 3 M= 2 3 & N= _ n=1 ^ (1+n⁻¹ )^2 1+2 n⁻¹ = _ n=1 ^ ( n+1 n )^2 ( n n+2 )= _ n=1 ^ ( (n+1)^2 n(n+

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