Most Important Selected Qs for JEE AdvancedPhysicsCenter of Mass, Momentum and Collision
In the shown figure, a particle of mass M 10 strikes the block of mass M with velocity v ₀ and gets attached to it. For what velocity v ₀ (in ms ⁻¹ ), the block B just able to leave the ground? (Given M=100 gm , K =880 ~N / m )
Correct answer
1
Step-by-step solution
From C.L.M. M 10 v ₀= 11 10 Mv v = v ₀ 11 ....(i) For block B to leave ground K ( x ₀+ x )=2 Mg ( . where . x ₀= Mg K ) x= Mg K ....(ii) From COE 11 10 Mgx - [ 1 2 ~K ( x ₀+ x )^2- 1 2 Kx ₀^2 ]=0- 1 2 11 10 Mv ^2 solving v₀=g 88 M K putting the value v ₀=1 ~ms ⁻¹