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Most Important Selected Qs for JEE AdvancedPhysicsElectromagnetic Induction

A conducting rod Pq is sliding on two parallel conducting rods with constant velocity in a uniform magnetic field of induction B =2 Wb / m ^2 as shown in the figure. The rods are connected with a circuit. What should be velocity of rod Pq (in m / s ) if current in 2 resistor is 0.1 A ?

Correct answer

5

Step-by-step solution

Current is 2 =0.1 ~A current in circuit =0.2 ~A equivalent resistance about A B=5 e = R =1 volts and also e = B V V = e B = 1 2 0.1 =5 ~m / s

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