Most Important Selected Qs for JEE AdvancedPhysicsElectromagnetic Induction
A non-conducting ring of radius R having uniformly distributed charge Q starts rotating about x-x^ axis passing through diameter with an angular acceleration as shown in the figure. Another small conducting ring having radius a ( R ) is kept fixed at the centre of bigger ring is such a way that axis x x^ is passing through its centre and perpendicular to its plane. If the resistance of small ring is r=1 , find the in
Correct answer
8
Step-by-step solution
aligned & d q= q 2 R R d = q 2 d & d i= d q T = q d 2 2 & d i= q 4 ^2 d & d B= ₀ d i(R )^2 2 R^3 & d B= ₀^ ₀ ^2 2 R ( q 4 ^2 ) d & B= ₀ q 16 R & =B a^2 & = a^2 ₀ q 16 R & = ₀ q a^2 16 R & | |= | d d t | & | |= ₀ q a^2 16 R & =8 volt & i= 8 1 =8 ~A . aligned