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Four identical point charges are fixed at the four corners of a square of a side length I. Another charged particle of mass m and charge +q is projected towards centre of square from a large distance along the line perpendicular to plane of square. The minimum value of initial velocity v₀ required to cross the square is? ( m =1 gm , l =4 2 ~m , Q =1 c , q =0.5 c )

Correct answer

3

Step-by-step solution

Particle will cross the square if it crosses the point of maximum potential between A and C -which is C itself. aligned & 1 2 m v₀^2=K+ 1 4 ₀ 4 Q^2 q (I / 2 ) & K 0 V₀^2=8 2 ( 1 4 ₀ ) ( Qq ml ) aligned

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